This question was previously asked in

SSC GD Previous Paper 23 (Held On: 1 March 2019 Shift 2)_English

Option 1 : 7040 g

Electric charges and coulomb's law (Basic)

40101

10 Questions
10 Marks
10 Mins

**Given :**

Height of the pipe = 28 cm

External Radius = (external Diameter/2) = 5 cm

Thickness of Pipe = 2 cm

**Formula :**

Volume of the pipe = π (R^{2} - r^{2})h ( where R = external radius, r = internal radius and h = height of the cylinder)

**Calculations :**

Internal radius = external radius - thickness

⇒ r = 5 - 2 = 3 cm

Volume of Cylinder = π (R^{2} - r^{2}) h

⇒ π (5^{2} - 3^{2}) × 28

⇒ 1408 cm^{3}

Weight = volume × density

⇒ 1408 × 5

⇒ 7040 gms

∴ **Weight of cylinder is 7040 gms**