This question was previously asked in

ESE Electronics 2012 Paper 2: Official Paper

Option 2 : 1.6 s

CT 1: Ratio and Proportion

2846

10 Questions
16 Marks
30 Mins

__Concept__:

The characteristic equation is given by:

1 + G(s) H(s) = 0

Also, the standard second-order characteristic equation is:

\({s^2} + 2\zeta {\omega _n}s + \omega _n^2 = 0\)

Settling Time is the time taken by the response to reach ± 2%, tolerance band.

\({e^{ - \xi {\omega _n}{t_s}}} = \pm 5\% \;\left( {or} \right) \pm 2\% \)

\({t_s} \simeq \frac{3}{{\xi {\omega _n}}}\) for a 5% tolerance band.

\({t_s} \simeq \frac{4}{{\xi {\omega _n}}}\) for 2% tolerance band

__Calculation__:

Characteristic equation:

s2 + 5s + 25 = 0

By comparing this with the standard second-order equation, we get:

\(\omega _n^2 = 25 \Rightarrow {\omega _n} = 5\)

\(2\zeta {\omega _n} = 5\)

\(\Rightarrow \zeta = \frac{5}{{2 \times 5}} = 0.5\)

Settling time is, therefore:

\({t_s} = \frac{4}{{0.5 \times 5}} = 1.6\;sec\)